LEPCHA VOWEL SIGN O·U+1C28

Character Information

Code Point
U+1C28
HEX
1C28
Unicode Plane
Basic Multilingual Plane
Category
Spacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B0 A8
11100001 10110000 10101000
UTF16 (big Endian)
1C 28
00011100 00101000
UTF16 (little Endian)
28 1C
00101000 00011100
UTF32 (big Endian)
00 00 1C 28
00000000 00000000 00011100 00101000
UTF32 (little Endian)
28 1C 00 00
00101000 00011100 00000000 00000000
HTML Entity
ᰨ
URI Encoded
%E1%B0%A8

Description

U+1C28, or the Lepcha Vowel Sign O, is a specialized character utilized in digital text for representing the "o" vowel sound in the Lepcha language. The Lepcha language is predominantly spoken by the Lepcha people, an indigenous community residing primarily in the Indian state of Sikkim and parts of Nepal. This unique character holds cultural significance within the Lepcha community as it contributes to the accurate representation and preservation of their linguistic heritage in written form. In typography and digital text contexts, U+1C28 plays a crucial role in ensuring proper orthographic rendition and clarity of meaning for readers familiar with the Lepcha script. Its precise application is vital for maintaining the integrity of the language and facilitating effective communication within the community.

How to type the symbol on Windows

Hold Alt and type 7208 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1C28. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1C28 to binary: 00011100 00101000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110000 10101000