LEPCHA VOWEL SIGN U·U+1C2A

Character Information

Code Point
U+1C2A
HEX
1C2A
Unicode Plane
Basic Multilingual Plane
Category
Spacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B0 AA
11100001 10110000 10101010
UTF16 (big Endian)
1C 2A
00011100 00101010
UTF16 (little Endian)
2A 1C
00101010 00011100
UTF32 (big Endian)
00 00 1C 2A
00000000 00000000 00011100 00101010
UTF32 (little Endian)
2A 1C 00 00
00101010 00011100 00000000 00000000
HTML Entity
ᰪ
URI Encoded
%E1%B0%AA

Description

The Unicode character U+1C2A, also known as Lepcha Vowel Sign U, holds a significant position in the realm of typography and digital text. It primarily functions within the Lepcha language, which is predominantly spoken in the Indian state of Sikkim. This specific character plays an essential role in representing vowel sounds in the Lepcha script, enabling accurate representation of words and phrases in this unique writing system. Lepcha Vowel Sign U is part of the Lepcha block of Unicode, which comprises various characters necessary for transcribing the Lepcha language digitally. The development of such characters has immensely contributed to preserving the linguistic heritage and promoting literacy in the Lepcha-speaking communities. As globalization continues to bridge cultural gaps through digital communication, characters like U+1C2A become increasingly crucial for maintaining the richness and diversity of linguistic expression across the world.

How to type the symbol on Windows

Hold Alt and type 7210 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1C2A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1C2A to binary: 00011100 00101010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110000 10101010