LIMBU SMALL LETTER MA·U+1936

Character Information

Code Point
U+1936
HEX
1936
Unicode Plane
Basic Multilingual Plane
Category
Spacing Mark

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A4 B6
11100001 10100100 10110110
UTF16 (big Endian)
19 36
00011001 00110110
UTF16 (little Endian)
36 19
00110110 00011001
UTF32 (big Endian)
00 00 19 36
00000000 00000000 00011001 00110110
UTF32 (little Endian)
36 19 00 00
00110110 00011001 00000000 00000000
HTML Entity
ᤶ
URI Encoded
%E1%A4%B6

Description

The Unicode character U+1936 represents the 'Limbú Small Letter Ma' in the Limbu script, which is primarily used for writing the Limbu language, spoken by over 300,000 people in eastern Nepal. As part of the Limbu alphabet, this character typically serves a role in digital text to convey meaning and nuance within the context of the Limbu language, enabling communication among native speakers. The Limbu script is an abugida system, where each character represents both a consonant and an inherent vowel 'a', but vowels can be changed by modifying certain characters or adding diacritics. U+1936 holds cultural significance for the Limbu community as it reflects their unique linguistic identity and heritage in the digital age, where preservation of indigenous languages is essential for maintaining cultural diversity.

How to type the symbol on Windows

Hold Alt and type 6454 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1936. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1936 to binary: 00011001 00110110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100100 10110110