DOES NOT CONTAIN AS NORMAL SUBGROUP OR EQUAL·U+22ED

Character Information

Code Point
U+22ED
HEX
22ED
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8B AD
11100010 10001011 10101101
UTF16 (big Endian)
22 ED
00100010 11101101
UTF16 (little Endian)
ED 22
11101101 00100010
UTF32 (big Endian)
00 00 22 ED
00000000 00000000 00100010 11101101
UTF32 (little Endian)
ED 22 00 00
11101101 00100010 00000000 00000000
HTML Entity
⋭
URI Encoded
%E2%8B%AD

Description

The Unicode character U+22ED, denoted as "⊉", is a mathematical symbol known as "does not contain as normal subgroup or equal." This symbol is mainly used in digital text to represent an algebraic expression that signifies the non-inclusion of a normal subgroup or equality. It is typically employed within mathematical formulas, particularly in set theory and group theory, which are branches of abstract mathematics dealing with sets and groups respectively. While U+22ED might not have a direct cultural or linguistic significance, its usage is crucial in precise communication of complex mathematical concepts. As an expert in Unicode and typography, it's essential to recognize the importance of such symbols in maintaining accuracy and clarity within digital text, especially when discussing advanced topics in mathematics.

How to type the symbol on Windows

Hold Alt and type 8941 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22ED. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22ED to binary: 00100010 11101101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001011 10101101