DOUBLE INTERSECTION·U+22D2

Character Information

Code Point
U+22D2
HEX
22D2
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8B 92
11100010 10001011 10010010
UTF16 (big Endian)
22 D2
00100010 11010010
UTF16 (little Endian)
D2 22
11010010 00100010
UTF32 (big Endian)
00 00 22 D2
00000000 00000000 00100010 11010010
UTF32 (little Endian)
D2 22 00 00
11010010 00100010 00000000 00000000
HTML Entity
⋒
URI Encoded
%E2%8B%92

Description

The Unicode character U+22D2 is known as the "Double Intersection" (∨). This symbol, primarily used in digital text, represents the symmetric difference operation in set theory and computer science. It signifies an event where two sets are compared, and an element is included if it is a member of either one or the other, but not both. The Double Intersection holds significance in linguistic, cultural, and technical contexts, as it serves as a crucial operator in mathematical logic, data structures, and algorithms. Its accurate representation allows for clear communication and understanding among professionals working with sets, programming languages, and problem-solving.

How to type the symbol on Windows

Hold Alt and type 8914 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22D2. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22D2 to binary: 00100010 11010010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001011 10010010