ELEMENT OF WITH DOT ABOVE·U+22F5

Character Information

Code Point
U+22F5
HEX
22F5
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8B B5
11100010 10001011 10110101
UTF16 (big Endian)
22 F5
00100010 11110101
UTF16 (little Endian)
F5 22
11110101 00100010
UTF32 (big Endian)
00 00 22 F5
00000000 00000000 00100010 11110101
UTF32 (little Endian)
F5 22 00 00
11110101 00100010 00000000 00000000
HTML Entity
⋵
URI Encoded
%E2%8B%B5

Description

The Unicode character U+22F5, known as "ELEMENT OF WITH DOT ABOVE," serves a specific purpose within digital typography. This glyph is primarily used in mathematical expressions and notations to represent an element with a dot above it. Its role is to denote the existence of a higher-order element or concept that supersedes the one below. In mathematical contexts, this character can be seen in algebraic structures where it represents an element within a set or group. The ELEMENT OF WITH DOT ABOVE does not have any significant cultural or linguistic implications, as its usage is mainly technical and limited to mathematical notation systems. However, its inclusion in the Unicode standard ensures accurate representation and communication of complex mathematical concepts across different digital platforms and devices.

How to type the symbol on Windows

Hold Alt and type 8949 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22F5. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22F5 to binary: 00100010 11110101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001011 10110101