EQUAL AND PARALLEL TO·U+22D5

Character Information

Code Point
U+22D5
HEX
22D5
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8B 95
11100010 10001011 10010101
UTF16 (big Endian)
22 D5
00100010 11010101
UTF16 (little Endian)
D5 22
11010101 00100010
UTF32 (big Endian)
00 00 22 D5
00000000 00000000 00100010 11010101
UTF32 (little Endian)
D5 22 00 00
11010101 00100010 00000000 00000000
HTML Entity
⋕
URI Encoded
%E2%8B%95

Description

The Unicode character U+22D5 is known as "EQUAL AND PARALLEL TO" (⊥). This mathematical symbol is predominantly used in digital text for expressing the concept of a non-standard or alternative parallelism relation between two geometric figures, such as lines. It signifies that two lines are neither equal nor parallel but lie at an angle that is considered analogous to the standard definitions of equality and parallelism. Although not widely used in everyday language, U+22D5 plays a significant role in advanced mathematical and technical texts, particularly those dealing with geometry and graph theory. Its usage contributes to precision and clarity when discussing specific geometric relationships that do not fall within the traditional parameters of equality or parallelism.

How to type the symbol on Windows

Hold Alt and type 8917 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22D5. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22D5 to binary: 00100010 11010101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001011 10010101