GREATER-THAN WITH DOT·U+22D7

Character Information

Code Point
U+22D7
HEX
22D7
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8B 97
11100010 10001011 10010111
UTF16 (big Endian)
22 D7
00100010 11010111
UTF16 (little Endian)
D7 22
11010111 00100010
UTF32 (big Endian)
00 00 22 D7
00000000 00000000 00100010 11010111
UTF32 (little Endian)
D7 22 00 00
11010111 00100010 00000000 00000000
HTML Entity
⋗
URI Encoded
%E2%8B%97

Description

The Unicode character U+22D7, known as the Greater-Than with Dot symbol (⋗), primarily serves a role in digital text for mathematical notation and logic systems. It is typically used to represent a greater-than comparison within specific contexts, often alongside other symbols like the Less-Than with Dot (U+22D6) or the Equal with Dot (U+2245). Although it may not be widely utilized in everyday typography, its use can be found within specialized fields such as computer programming, engineering, and scientific documentation. There is no notable cultural, linguistic, or technical context associated with this specific symbol.

How to type the symbol on Windows

Hold Alt and type 8919 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22D7. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22D7 to binary: 00100010 11010111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001011 10010111