LESS-THAN EQUAL TO OR GREATER-THAN·U+22DA

Character Information

Code Point
U+22DA
HEX
22DA
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8B 9A
11100010 10001011 10011010
UTF16 (big Endian)
22 DA
00100010 11011010
UTF16 (little Endian)
DA 22
11011010 00100010
UTF32 (big Endian)
00 00 22 DA
00000000 00000000 00100010 11011010
UTF32 (little Endian)
DA 22 00 00
11011010 00100010 00000000 00000000
HTML Entity
⋚
URI Encoded
%E2%8B%9A

Description

The Unicode character U+22DA, known as "Less-Than or Greater-Than" (≤), is a symbol that holds significant importance in digital text, particularly within mathematical equations and scientific notation. Its primary role is to represent an inequality between two numbers, indicating that the value on the left side of the symbol is either less than or equal to the value on the right side. This symbol provides clarity when conveying relationships between variables and constants, and it is widely used in programming languages and computational software for its concise representation of these relationships. Additionally, U+22DA can be found in various mathematical documents, educational materials, and engineering designs to clearly communicate inequality conditions.

How to type the symbol on Windows

Hold Alt and type 8922 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22DA. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22DA to binary: 00100010 11011010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001011 10011010