Character Information

Code Point
U+22B8
HEX
22B8
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8A B8
11100010 10001010 10111000
UTF16 (big Endian)
22 B8
00100010 10111000
UTF16 (little Endian)
B8 22
10111000 00100010
UTF32 (big Endian)
00 00 22 B8
00000000 00000000 00100010 10111000
UTF32 (little Endian)
B8 22 00 00
10111000 00100010 00000000 00000000
HTML Entity
⊸
URI Encoded
%E2%8A%B8

Description

The Unicode character U+22B8, known as the MULTIMAP symbol, is a specialized mathematical sign used to denote a mapping between different structures in algebraic topology, specifically in homotopy theory. Its typical usage lies within digital text in fields of mathematics and computer science where it helps illustrate complex relationships between mathematical objects. The MULTIMAP symbol plays an important role in the study of algebraic structures and has been widely utilized in academic publications, research papers, and textbooks. It is also relevant in the context of LaTeX typesetting, a high-quality typesetting system commonly used for scientific documentation. Overall, the MULTIMAP character is an essential tool for expressing intricate mathematical concepts and relationships in digital text.

How to type the symbol on Windows

Hold Alt and type 8888 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+22B8. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+22B8 to binary: 00100010 10111000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001010 10111000