MATHEMATICAL LEFT ANGLE BRACKET·U+27E8

Character Information

Code Point
U+27E8
HEX
27E8
Unicode Plane
Basic Multilingual Plane
Category
Open Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 9F A8
11100010 10011111 10101000
UTF16 (big Endian)
27 E8
00100111 11101000
UTF16 (little Endian)
E8 27
11101000 00100111
UTF32 (big Endian)
00 00 27 E8
00000000 00000000 00100111 11101000
UTF32 (little Endian)
E8 27 00 00
11101000 00100111 00000000 00000000
HTML Entity
⟨
URI Encoded
%E2%9F%A8

Description

The Unicode character U+27E8, known as the Mathematical Left Angle Bracket, plays a significant role in digital text, particularly within mathematical and scientific contexts. It is commonly used to denote inclusions or subsets in set theory and logic. Its primary function is to represent the less-than symbol (<) in an upright, open-ended style, visually indicating that the content enclosed by it is part of a larger set. This character's utility spans across various fields, including computer programming, data analysis, and mathematical notation systems. Despite its specialized use, U+27E8 remains a crucial tool for clear and concise communication in these domains, ensuring accurate representation of relationships between sets and values.

How to type the symbol on Windows

Hold Alt and type 10216 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+27E8. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+27E8 to binary: 00100111 11101000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10011111 10101000