DOUBLE RIGHT ARC LESS-THAN BRACKET·U+2996

Character Information

Code Point
U+2996
HEX
2996
Unicode Plane
Basic Multilingual Plane
Category
Close Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A6 96
11100010 10100110 10010110
UTF16 (big Endian)
29 96
00101001 10010110
UTF16 (little Endian)
96 29
10010110 00101001
UTF32 (big Endian)
00 00 29 96
00000000 00000000 00101001 10010110
UTF32 (little Endian)
96 29 00 00
10010110 00101001 00000000 00000000
HTML Entity
⦖
URI Encoded
%E2%A6%96

Description

The Unicode character U+2996, known as the "DOUBLE RIGHT ARC LESS-THAN BRACKET", is a less common mathematical symbol used primarily in digital text for its distinct visual appearance and specific function. It serves as an open brace that denotes the start of an integral or summation in mathematics. The character is part of the Miscellaneous Technical category within Unicode, which includes various symbols and characters used in technology and computing. Although not commonly used in everyday writing, it holds significant importance in specific contexts like computer programming, engineering, and advanced mathematics, where precise notation is crucial. Despite its specialized nature, the DOUBLE RIGHT ARC LESS-THAN BRACKET plays a critical role in ensuring clarity and accurate interpretation of complex formulas and algorithms.

How to type the symbol on Windows

Hold Alt and type 10646 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2996. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2996 to binary: 00101001 10010110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10100110 10010110