REVERSED ANGLE WITH UNDERBAR·U+29A5

Character Information

Code Point
U+29A5
HEX
29A5
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 A6 A5
11100010 10100110 10100101
UTF16 (big Endian)
29 A5
00101001 10100101
UTF16 (little Endian)
A5 29
10100101 00101001
UTF32 (big Endian)
00 00 29 A5
00000000 00000000 00101001 10100101
UTF32 (little Endian)
A5 29 00 00
10100101 00101001 00000000 00000000
HTML Entity
⦥
URI Encoded
%E2%A6%A5

Description

The character U+29A5, known as the Reversed Angle with Underbar, is a typographical symbol with specific applications in digital text. It serves primarily as an indicator of the reversal of the direction of a text or flow of information, often used to represent mathematical concepts where angles are involved. In some instances, it is also employed as a punctuation mark for certain types of documents and publications requiring precise formatting. The Reversed Angle with Underbar holds no significant cultural or linguistic context, but its usage in technical documents demonstrates its importance in specific fields such as engineering, computer programming, and mathematics. Its clear and accurate application is essential to avoid confusion and ensure proper interpretation of the text or data it represents.

How to type the symbol on Windows

Hold Alt and type 10661 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+29A5. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+29A5 to binary: 00101001 10100101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10100110 10100101