LEFT RIGHT BLACK ARROW·U+2B0C

Character Information

Code Point
U+2B0C
HEX
2B0C
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 AC 8C
11100010 10101100 10001100
UTF16 (big Endian)
2B 0C
00101011 00001100
UTF16 (little Endian)
0C 2B
00001100 00101011
UTF32 (big Endian)
00 00 2B 0C
00000000 00000000 00101011 00001100
UTF32 (little Endian)
0C 2B 00 00
00001100 00101011 00000000 00000000
HTML Entity
⬌
URI Encoded
%E2%AC%8C

Description

The Unicode character U+2B0C, known as the Left Right Black Arrow, plays a crucial role in digital text as an essential symbol for directional indicators. This glyph is widely used across various digital platforms, including software applications, websites, and mobile devices. Its primary function lies in illustrating directional movement or flow, making it indispensable in fields such as programming, game development, and technical documentation. Additionally, the Left Right Black Arrow often appears in mathematical notation, particularly within problem-solving contexts and algorithmic expressions, to denote a change of direction or a shift between two states. Despite its frequent usage in the digital realm, this character has no cultural, linguistic, or regional significance beyond its technical function.

How to type the symbol on Windows

Hold Alt and type 11020 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2B0C. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2B0C to binary: 00101011 00001100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101100 10001100