LEFTWARDS ARROW ABOVE ALMOST EQUAL TO·U+2B4A

Character Information

Code Point
U+2B4A
HEX
2B4A
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 AD 8A
11100010 10101101 10001010
UTF16 (big Endian)
2B 4A
00101011 01001010
UTF16 (little Endian)
4A 2B
01001010 00101011
UTF32 (big Endian)
00 00 2B 4A
00000000 00000000 00101011 01001010
UTF32 (little Endian)
4A 2B 00 00
01001010 00101011 00000000 00000000
HTML Entity
⭊
URI Encoded
%E2%AD%8A

Description

The Unicode character U+2B4A, known as the Leftwards Arrow Above Almost Equal To, is a typographic symbol used primarily in mathematical and scientific digital text to represent an inequality. Specifically, it denotes a leftward-pointing arrow that signifies the relationship "almost equal to" or "less than or approximately equal to," often represented by the symbol ≪ or ⋠ in text. This character is particularly useful in cases where standard inequality symbols, such as less than (<) and greater than (>) are not expressive enough for the intended meaning. Although it does not have a widespread cultural significance, it plays an important role in technical contexts like computer science, mathematics, and engineering by providing precise representation of certain relationships or conditions.

How to type the symbol on Windows

Hold Alt and type 11082 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2B4A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2B4A to binary: 00101011 01001010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101101 10001010