LEFTWARDS ARROW WITH TAIL WITH VERTICAL STROKE·U+2B39

Character Information

Code Point
U+2B39
HEX
2B39
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 AC B9
11100010 10101100 10111001
UTF16 (big Endian)
2B 39
00101011 00111001
UTF16 (little Endian)
39 2B
00111001 00101011
UTF32 (big Endian)
00 00 2B 39
00000000 00000000 00101011 00111001
UTF32 (little Endian)
39 2B 00 00
00111001 00101011 00000000 00000000
HTML Entity
⬹
URI Encoded
%E2%AC%B9

Description

The Unicode character U+2B39, known as the "Leftwards Arrow with Tail with Vertical Stroke," serves a specific function in digital text communication. This symbol is predominantly used in programming, mathematics, and engineering contexts to indicate leftward movement or directionality when combined with other symbols or elements. In technical documentation and algorithms, it often signifies the reversal of a sequence or flow of data. Its vertical stroke distinguishes it from the more commonly used "Leftwards Arrow with Tail" (U+2190), making it particularly useful in contexts where precision and clarity are essential.

How to type the symbol on Windows

Hold Alt and type 11065 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2B39. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2B39 to binary: 00101011 00111001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101100 10111001