LEFTWARDS TWO-HEADED TRIPLE DASH ARROW·U+2B37

Character Information

Code Point
U+2B37
HEX
2B37
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 AC B7
11100010 10101100 10110111
UTF16 (big Endian)
2B 37
00101011 00110111
UTF16 (little Endian)
37 2B
00110111 00101011
UTF32 (big Endian)
00 00 2B 37
00000000 00000000 00101011 00110111
UTF32 (little Endian)
37 2B 00 00
00110111 00101011 00000000 00000000
HTML Entity
⬷
URI Encoded
%E2%AC%B7

Description

U+2B37, known as the Leftwards Two-Headed Triple Dash Arrow, is a special character used in digital text to represent a specific mathematical operation. This character is commonly utilized in mathematical notations within digital text to express the derivative of a function. Its primary role lies in symbolizing the derivative operator, which denotes the rate at which a given functional value changes with respect to its input variable. The Leftwards Two-Headed Triple Dash Arrow often appears alongside other arrows like the Rightwards Two-Headed Triple Dash Arrow (U+2B3A) in mathematical contexts. While this character holds no cultural, linguistic, or technical significance beyond its role as a mathematical operator, it remains an essential tool for those working with derivatives and related concepts in mathematics, physics, and engineering.

How to type the symbol on Windows

Hold Alt and type 11063 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2B37. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2B37 to binary: 00101011 00110111. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10101100 10110111