APL FUNCTIONAL SYMBOL GREATER-THAN DIAERESIS·U+2369

Character Information

Code Point
U+2369
HEX
2369
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8D A9
11100010 10001101 10101001
UTF16 (big Endian)
23 69
00100011 01101001
UTF16 (little Endian)
69 23
01101001 00100011
UTF32 (big Endian)
00 00 23 69
00000000 00000000 00100011 01101001
UTF32 (little Endian)
69 23 00 00
01101001 00100011 00000000 00000000
HTML Entity
⍩
URI Encoded
%E2%8D%A9

Description

The Unicode character U+2369, also known as the APL Functional Symbol Greater-Than Diaeresis, plays a significant role in digital text communication, particularly within mathematical and computational disciplines. Its primary function is to denote a greater-than relationship with a diaeresis marking, enabling precise expression of mathematical or logical statements. This symbol is commonly used in the APL programming language, which relies heavily on such characters for succinct representation of complex operations. As an essential tool in various fields like mathematics, computer science, and engineering, the U+2369 character aids in conveying accurate and concise information, contributing to the progression of knowledge in these disciplines.

How to type the symbol on Windows

Hold Alt and type 9065 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2369. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2369 to binary: 00100011 01101001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001101 10101001