APL FUNCTIONAL SYMBOL QUAD DEL·U+2354

Character Information

Code Point
U+2354
HEX
2354
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8D 94
11100010 10001101 10010100
UTF16 (big Endian)
23 54
00100011 01010100
UTF16 (little Endian)
54 23
01010100 00100011
UTF32 (big Endian)
00 00 23 54
00000000 00000000 00100011 01010100
UTF32 (little Endian)
54 23 00 00
01010100 00100011 00000000 00000000
HTML Entity
⍔
URI Encoded
%E2%8D%94

Description

U+2354, the APL Functional Symbol Quad Del (⊗), plays a significant role in digital text, particularly within the realm of computer science and mathematics. As a part of the APL programming language developed by Alonzo Church, it serves as a functional symbol for multiplication. The character's utility extends to its use in typography and mathematical notation, offering an alternative representation for multiplication. In digital text, ⊗ often substitutes the traditional x or * symbols, providing a distinct visual cue for mathematicians, programmers, and students alike. Despite its niche application, this APL Functional Symbol Quad Del holds a prominent position in the technical context of digital text and mathematical notation.

How to type the symbol on Windows

Hold Alt and type 9044 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+2354. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+2354 to binary: 00100011 01010100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001101 10010100