APL FUNCTIONAL SYMBOL QUAD JOT·U+233B

Character Information

Code Point
U+233B
HEX
233B
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8C BB
11100010 10001100 10111011
UTF16 (big Endian)
23 3B
00100011 00111011
UTF16 (little Endian)
3B 23
00111011 00100011
UTF32 (big Endian)
00 00 23 3B
00000000 00000000 00100011 00111011
UTF32 (little Endian)
3B 23 00 00
00111011 00100011 00000000 00000000
HTML Entity
⌻
URI Encoded
%E2%8C%BB

Description

The Unicode character U+233B, known as the APL Functional Symbol Quad Jot, holds a significant place in the world of digital typography and mathematics. As an ASCII character set, it was created primarily for use in the programming language APL (A Programming Language), which emphasizes array-based computation. The Quad Jot symbol is used as a functional notation, signifying an operation or function that acts on its arguments. Its usage often involves complex mathematical formulas and algorithms, particularly within the realm of scientific computing and engineering applications. Despite being less known to mainstream users, it has a vital role in specialized fields where efficiency and brevity are of high importance. In these contexts, the Quad Jot symbol plays a crucial part in enabling concise communication and precise computation.

How to type the symbol on Windows

Hold Alt and type 9019 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+233B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+233B to binary: 00100011 00111011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001100 10111011