BOTTOM SQUARE BRACKET OVER TOP SQUARE BRACKET·U+23B6

Character Information

Code Point
U+23B6
HEX
23B6
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8E B6
11100010 10001110 10110110
UTF16 (big Endian)
23 B6
00100011 10110110
UTF16 (little Endian)
B6 23
10110110 00100011
UTF32 (big Endian)
00 00 23 B6
00000000 00000000 00100011 10110110
UTF32 (little Endian)
B6 23 00 00
10110110 00100011 00000000 00000000
HTML Entity
⎶
URI Encoded
%E2%8E%B6

Description

The Unicode character U+23B6, known as BOTTOM SQUARE BRACKET OVER TOP SQUARE BRACKET, is a rarely used typographic symbol that combines two square brackets in an intersecting manner. In digital text, this symbol might be used in programming languages or computer code to denote specific syntax or formatting. It may also appear in mathematical or technical documents where it can represent a particular operation or concept. However, due to its rarity and potential confusion with more commonly used symbols, U+23B6 is not widely recognized in popular culture or everyday language. Despite its limited usage, the BOTTOM SQUARE BRACKET OVER TOP SQUARE BRACKET holds significance for those working in specialized fields where the symbol may be necessary for proper communication and expression of ideas.

How to type the symbol on Windows

Hold Alt and type 9142 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23B6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23B6 to binary: 00100011 10110110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001110 10110110