DENTISTRY SYMBOL LIGHT VERTICAL AND BOTTOM LEFT·U+23CC

Character Information

Code Point
U+23CC
HEX
23CC
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 8C
11100010 10001111 10001100
UTF16 (big Endian)
23 CC
00100011 11001100
UTF16 (little Endian)
CC 23
11001100 00100011
UTF32 (big Endian)
00 00 23 CC
00000000 00000000 00100011 11001100
UTF32 (little Endian)
CC 23 00 00
11001100 00100011 00000000 00000000
HTML Entity
⏌
URI Encoded
%E2%8F%8C

Description

The Unicode character U+23CC, also known as the Dentistry Symbol Light Vertical and Bottom Left, serves a specific purpose in digital text. Primarily used in dentistry and related fields, this symbol assists in depicting the position of teeth or dental elements in a patient's mouth. It is particularly useful for precise communication between dental professionals about a patient's oral health condition or during treatment planning. In addition to its role in healthcare, this character might also be used in technical documents or educational materials where precise positioning of objects needs to be conveyed visually. While not a widely recognized symbol outside these specific contexts, the Dentistry Symbol Light Vertical and Bottom Left plays an important role within the dental community and related industries.

How to type the symbol on Windows

Hold Alt and type 9164 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23CC. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23CC to binary: 00100011 11001100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10001100