DENTISTRY SYMBOL LIGHT VERTICAL AND TOP RIGHT·U+23BE

Character Information

Code Point
U+23BE
HEX
23BE
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8E BE
11100010 10001110 10111110
UTF16 (big Endian)
23 BE
00100011 10111110
UTF16 (little Endian)
BE 23
10111110 00100011
UTF32 (big Endian)
00 00 23 BE
00000000 00000000 00100011 10111110
UTF32 (little Endian)
BE 23 00 00
10111110 00100011 00000000 00000000
HTML Entity
⎾
URI Encoded
%E2%8E%BE

Description

The Unicode character U+23BE, also known as the Dentistry Symbol Light Vertical and Top Right, primarily serves a specialized function in digital text. It is mainly used within the field of dentistry to represent various dental procedures or concepts in technical documentation, research papers, and educational materials. In these contexts, it can be employed for depicting specific aspects of dental anatomy or illustrating intricate processes, thus enhancing clarity and understanding for professionals and students alike. While not widely recognized outside the dental community, the Dentistry Symbol Light Vertical and Top Right plays a crucial role in ensuring accurate communication and efficient collaboration among experts in this specialized domain.

How to type the symbol on Windows

Hold Alt and type 9150 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23BE. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23BE to binary: 00100011 10111110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001110 10111110