DENTISTRY SYMBOL LIGHT VERTICAL AND WAVE·U+23C6

Character Information

Code Point
U+23C6
HEX
23C6
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 86
11100010 10001111 10000110
UTF16 (big Endian)
23 C6
00100011 11000110
UTF16 (little Endian)
C6 23
11000110 00100011
UTF32 (big Endian)
00 00 23 C6
00000000 00000000 00100011 11000110
UTF32 (little Endian)
C6 23 00 00
11000110 00100011 00000000 00000000
HTML Entity
⏆
URI Encoded
%E2%8F%86

Description

The Unicode character U+23C6, known as the Dentistry Symbol Light Vertical and Wave, is a specialized symbol used primarily in digital text for dental and orthodontic applications. In its typical usage, this character represents a light force applied in various dental procedures such as moving teeth during orthodontic treatment. The symbol combines two distinct components: a vertical line that signifies the direction of force, and a wave-like pattern that indicates its gentle nature. This character is particularly relevant within the dental and orthodontic community, where it helps convey essential information about treatment techniques and methods in a clear, concise manner. Although this symbol may not be widely recognized outside of these fields, it plays an important role in accurate communication within the dental profession.

How to type the symbol on Windows

Hold Alt and type 9158 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23C6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23C6 to binary: 00100011 11000110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10000110