DENTISTRY SYMBOL LIGHT VERTICAL WITH CIRCLE·U+23C0

Character Information

Code Point
U+23C0
HEX
23C0
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 80
11100010 10001111 10000000
UTF16 (big Endian)
23 C0
00100011 11000000
UTF16 (little Endian)
C0 23
11000000 00100011
UTF32 (big Endian)
00 00 23 C0
00000000 00000000 00100011 11000000
UTF32 (little Endian)
C0 23 00 00
11000000 00100011 00000000 00000000
HTML Entity
⏀
URI Encoded
%E2%8F%80

Description

The Unicode character U+23C0, known as the Dentistry Symbol Light Vertical with Circle, is a specialized symbol primarily used in medical and dental fields for representation in digital text. This typographic glyph serves a crucial role in the documentation of various treatments, procedures, and devices in dentistry. Its lightweight design allows for easy incorporation into text without overshadowing other symbols or characters, while its unique circle element provides visual distinction. Despite its limited usage scope, this character is essential within its specific domain, aiding professionals in conveying complex information accurately and efficiently. The Dentistry Symbol Light Vertical with Circle is not associated with any notable cultural or linguistic context outside of its technical application. As digital text becomes increasingly prevalent, the importance of having an accurate representation for specialized symbols such as U+23C0 cannot be understated.

How to type the symbol on Windows

Hold Alt and type 9152 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23C0. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23C0 to binary: 00100011 11000000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10000000