DENTISTRY SYMBOL LIGHT VERTICAL WITH TRIANGLE·U+23C3

Character Information

Code Point
U+23C3
HEX
23C3
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 83
11100010 10001111 10000011
UTF16 (big Endian)
23 C3
00100011 11000011
UTF16 (little Endian)
C3 23
11000011 00100011
UTF32 (big Endian)
00 00 23 C3
00000000 00000000 00100011 11000011
UTF32 (little Endian)
C3 23 00 00
11000011 00100011 00000000 00000000
HTML Entity
⏃
URI Encoded
%E2%8F%83

Description

The Unicode character U+23C3, known as the DENTISTRY SYMBOL LIGHT VERTICAL WITH TRIANGLE, is a specialized typographical symbol predominantly used in digital text related to dentistry and medical fields. Its primary purpose is to represent an area in the mouth, such as the dental arch or oral cavity, where a specific treatment or examination is focused. This character can be particularly useful in dental diagrams, patient records, or research documents that require precise notation of spatial relationships within the oral cavity. While this character has no direct cultural, linguistic, or widely-recognized technical context outside its specialized applications, it serves as an essential tool for accurate and clear communication within the fields of dentistry and oral healthcare.

How to type the symbol on Windows

Hold Alt and type 9155 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23C3. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23C3 to binary: 00100011 11000011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10000011