HORIZONTAL SCAN LINE-7·U+23BC

Character Information

Code Point
U+23BC
HEX
23BC
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8E BC
11100010 10001110 10111100
UTF16 (big Endian)
23 BC
00100011 10111100
UTF16 (little Endian)
BC 23
10111100 00100011
UTF32 (big Endian)
00 00 23 BC
00000000 00000000 00100011 10111100
UTF32 (little Endian)
BC 23 00 00
10111100 00100011 00000000 00000000
HTML Entity
⎼
URI Encoded
%E2%8E%BC

Description

The Unicode character U+23BC represents the "Horizontal Scan Line-7" in typography and digital text. This character is predominantly used in the context of computer graphics and digital typography to depict horizontal scan lines, which are essential components for understanding how raster images are formed on a screen. These scan lines play a crucial role in the process of rendering visual content on digital displays, including monitors and televisions. The U+23BC character specifically denotes the seventh horizontal scan line, which is important for precise alignment and positioning of elements within the digital space. Although this character may not have a significant cultural or linguistic context, it remains vital in the technical realm for accurate representation and manipulation of digital text and visual content on various devices.

How to type the symbol on Windows

Hold Alt and type 9148 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23BC. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23BC to binary: 00100011 10111100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001110 10111100