LEFT CURLY BRACKET LOWER HOOK·U+23A9

Character Information

Code Point
U+23A9
HEX
23A9
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8E A9
11100010 10001110 10101001
UTF16 (big Endian)
23 A9
00100011 10101001
UTF16 (little Endian)
A9 23
10101001 00100011
UTF32 (big Endian)
00 00 23 A9
00000000 00000000 00100011 10101001
UTF32 (little Endian)
A9 23 00 00
10101001 00100011 00000000 00000000
HTML Entity
⎩
URI Encoded
%E2%8E%A9

Description

The Unicode character U+23A9, known as the Left Curly Bracket Lower Hook, is a typographical symbol that holds significant value in digital text. It primarily serves to denote a range of values or elements in mathematical expressions and programming languages. In computer science, particularly in the realm of data structures and algorithms, the Left Curly Bracket Lower Hook is used as a part of the syntax for defining and accessing array elements. The character's unique shape distinguishes it from other brackets, making it easier to read and comprehend code. While the Left Curly Bracket Lower Hook may not be a widely recognized symbol in everyday writing, it plays an essential role in various technical contexts, contributing to the clarity and precision of digital text.

How to type the symbol on Windows

Hold Alt and type 9129 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23A9. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23A9 to binary: 00100011 10101001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001110 10101001