METRICAL PENTASEME·U+23D9

Character Information

Code Point
U+23D9
HEX
23D9
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 99
11100010 10001111 10011001
UTF16 (big Endian)
23 D9
00100011 11011001
UTF16 (little Endian)
D9 23
11011001 00100011
UTF32 (big Endian)
00 00 23 D9
00000000 00000000 00100011 11011001
UTF32 (little Endian)
D9 23 00 00
11011001 00100011 00000000 00000000
HTML Entity
⏙
URI Encoded
%E2%8F%99

Description

The Unicode character U+23D9, known as the Metrical Pentaseme, is a typographical symbol used primarily in music notation software and other digital text applications. Its primary role is to represent the pentaseme, or the group of five adjacent notes, in musical scores. This character plays a vital role in music transcription and composition, making it easier for composers, musicians, and conductors to understand the structure and flow of a piece of music. The Metrical Pentaseme has no specific cultural or linguistic context; its usage is purely technical and serves as a tool for musical understanding and notation. Its inclusion in Unicode ensures that this character can be used consistently across various software platforms, enhancing interoperability and collaboration within the global music community.

How to type the symbol on Windows

Hold Alt and type 9177 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23D9. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23D9 to binary: 00100011 11011001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10011001