METRICAL TWO SHORTS JOINED·U+23D6

Character Information

Code Point
U+23D6
HEX
23D6
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F 96
11100010 10001111 10010110
UTF16 (big Endian)
23 D6
00100011 11010110
UTF16 (little Endian)
D6 23
11010110 00100011
UTF32 (big Endian)
00 00 23 D6
00000000 00000000 00100011 11010110
UTF32 (little Endian)
D6 23 00 00
11010110 00100011 00000000 00000000
HTML Entity
⏖
URI Encoded
%E2%8F%96

Description

U+23D6, also known as the Metrical Two Shorts Joined, is a lesser-known Unicode character with a specific role in digital text. It primarily serves as a typographical symbol used to represent musical notation, specifically in the context of metrical analysis and rhythmic patterns. This character allows for greater precision when representing complex rhythms or time signatures in music theory and composition. Although it may not be widely recognized or used by the general public, the Metrical Two Shorts Joined holds significance within specialized communities such as musicians, composers, and music educators who rely on precise notation to convey intricate rhythmic concepts.

How to type the symbol on Windows

Hold Alt and type 9174 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23D6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23D6 to binary: 00100011 11010110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10010110