TOP SQUARE BRACKET·U+23B4

Character Information

Code Point
U+23B4
HEX
23B4
Unicode Plane
Basic Multilingual Plane
Category
Other Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8E B4
11100010 10001110 10110100
UTF16 (big Endian)
23 B4
00100011 10110100
UTF16 (little Endian)
B4 23
10110100 00100011
UTF32 (big Endian)
00 00 23 B4
00000000 00000000 00100011 10110100
UTF32 (little Endian)
B4 23 00 00
10110100 00100011 00000000 00000000
HTML Entity
⎴
URI Encoded
%E2%8E%B4

Description

The Unicode character U+23B4, also known as the Top Square Bracket, holds a unique position within the realm of typography and digital text. This non-printing control character is primarily used to enclose or isolate specific sections of text in typesetting, thereby ensuring that these portions are treated distinctly during formatting processes. The top square bracket finds its utility in mathematical notation, where it aids in representing various concepts such as limits and differentials, and in computer programming, where it serves as a delimiter in context-free grammars and syntax parsing. Despite its seemingly mundane role, the Top Square Bracket plays an indispensable part in maintaining textual integrity across various digital platforms, thereby solidifying its significance within the world of typography and digital communication.

How to type the symbol on Windows

Hold Alt and type 9140 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23B4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23B4 to binary: 00100011 10110100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001110 10110100