TOP TORTOISE SHELL BRACKET·U+23E0

Character Information

Code Point
U+23E0
HEX
23E0
Unicode Plane
Basic Multilingual Plane
Category
Math Symbol

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E2 8F A0
11100010 10001111 10100000
UTF16 (big Endian)
23 E0
00100011 11100000
UTF16 (little Endian)
E0 23
11100000 00100011
UTF32 (big Endian)
00 00 23 E0
00000000 00000000 00100011 11100000
UTF32 (little Endian)
E0 23 00 00
11100000 00100011 00000000 00000000
HTML Entity
⏠
URI Encoded
%E2%8F%A0

Description

The Unicode character U+23E0 represents the TOP TORTOISE SHELL BRACKET (❪). In digital text, this symbol is primarily used as a pair of brackets with a unique appearance that resembles the shell of a tortoise. Its curved design, with pointed ends and a continuous curve along the upper edge, sets it apart from other bracket characters. This distinctive shape may be employed in typography or graphic design to create visual interest, enhance readability, or provide structural delineation within text content. Although this character is not widely used in everyday digital communication, its availability in Unicode signifies the extensive range of symbols and characters that can be represented and utilized across various platforms and languages.

How to type the symbol on Windows

Hold Alt and type 9184 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+23E0. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+23E0 to binary: 00100011 11100000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100010 10001111 10100000