MONGOLIAN LETTER MANCHU ALI GALI LHA·U+18AA

Character Information

Code Point
U+18AA
HEX
18AA
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A2 AA
11100001 10100010 10101010
UTF16 (big Endian)
18 AA
00011000 10101010
UTF16 (little Endian)
AA 18
10101010 00011000
UTF32 (big Endian)
00 00 18 AA
00000000 00000000 00011000 10101010
UTF32 (little Endian)
AA 18 00 00
10101010 00011000 00000000 00000000
HTML Entity
ᢪ
URI Encoded
%E1%A2%AA

Description

U+18AA is the Unicode character code for "MONGOLIAN LETTER MANCHU ALI GALI LHA," a letter used in the Manchu script, which was historically employed to write the Manchu language. This script, developed during the Qing Dynasty (1644-1912) of China, is part of the Mongolic family of scripts and is closely related to other languages such as Old Turkic and Mongolian. The character U+18AA specifically represents a specific phonetic sound in Manchu language, contributing to the grammatical structure and lexicon of the language. In digital text, this character plays a crucial role in maintaining the integrity of historical documents, academic research, and cultural preservation efforts for the Manchu language. It is also used in modern software development for supporting multi-language platforms, thus enabling the continued use and understanding of this unique script by scholars and enthusiasts around the world.

How to type the symbol on Windows

Hold Alt and type 6314 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+18AA. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+18AA to binary: 00011000 10101010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100010 10101010