MONGOLIAN LETTER MANCHU ALI GALI NGA·U+189B

Character Information

Code Point
U+189B
HEX
189B
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A2 9B
11100001 10100010 10011011
UTF16 (big Endian)
18 9B
00011000 10011011
UTF16 (little Endian)
9B 18
10011011 00011000
UTF32 (big Endian)
00 00 18 9B
00000000 00000000 00011000 10011011
UTF32 (little Endian)
9B 18 00 00
10011011 00011000 00000000 00000000
HTML Entity
ᢛ
URI Encoded
%E1%A2%9B

Description

The character U+189B, Mongolian Letter Manchu Ali Galí Nga, plays a crucial role in the digital representation of the Manchu script, which is part of the larger Mongolic language family. Typically used in digital text, this symbol helps preserve and promote Manchu culture by enabling accurate reproduction of written materials in both online and offline contexts. U+189B contributes to the proper display of historical Manchu texts, supporting linguistic and cultural research, as well as facilitating communication within the Manchu-speaking community. As part of the Unicode Standard, it ensures the correct encoding and compatibility across different platforms, contributing to the preservation of this rich linguistic heritage.

How to type the symbol on Windows

Hold Alt and type 6299 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+189B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+189B to binary: 00011000 10011011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100010 10011011