MONGOLIAN LETTER MANCHU ALI GALI TA·U+18A0

Character Information

Code Point
U+18A0
HEX
18A0
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A2 A0
11100001 10100010 10100000
UTF16 (big Endian)
18 A0
00011000 10100000
UTF16 (little Endian)
A0 18
10100000 00011000
UTF32 (big Endian)
00 00 18 A0
00000000 00000000 00011000 10100000
UTF32 (little Endian)
A0 18 00 00
10100000 00011000 00000000 00000000
HTML Entity
ᢠ
URI Encoded
%E1%A2%A0

Description

U+18A0 Mongolian Letter Manchu Ali Gali Ta is a Unicode character primarily used in digital texts to represent the Manchu script, which was employed for writing the Manchu language. This language was historically spoken by the Manchus, an ethnic group that ruled over China during the Qing Dynasty (1644-1912). Although the Manchu script is now considered obsolete and primarily used for linguistic and historical studies, U+18A0 remains a vital component in accurately encoding and displaying texts containing classical or historical Manchu content. As an expert in Unicode and typography, it's important to recognize the significance of this character in preserving and studying the cultural heritage of the Manchu people and their contributions to Chinese history.

How to type the symbol on Windows

Hold Alt and type 6304 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+18A0. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+18A0 to binary: 00011000 10100000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100010 10100000