MONGOLIAN LETTER MANCHU ALI GALI ZHA·U+18A4

Character Information

Code Point
U+18A4
HEX
18A4
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A2 A4
11100001 10100010 10100100
UTF16 (big Endian)
18 A4
00011000 10100100
UTF16 (little Endian)
A4 18
10100100 00011000
UTF32 (big Endian)
00 00 18 A4
00000000 00000000 00011000 10100100
UTF32 (little Endian)
A4 18 00 00
10100100 00011000 00000000 00000000
HTML Entity
ᢤ
URI Encoded
%E1%A2%A4

Description

The Unicode character U+18A4, Mongolian Letter Manchu Ali Gali Zha, is a unique symbol used predominantly in digital text representation for the Manchu script, which was historically utilized by the Manchu people of Northeast China. This letter is an integral part of the Manchu language, a Tungusic language that belongs to the larger Altaic language family. In digital communication and publishing, U+18A4 enables the accurate representation of text in the Manchu script, facilitating the preservation and promotion of this culturally significant language. The character's significance is rooted in its role within the broader context of linguistic diversity, as it contributes to the rich tapestry of global communication by providing a means for expressing distinct cultural identities and historical perspectives through written form.

How to type the symbol on Windows

Hold Alt and type 6308 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+18A4. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+18A4 to binary: 00011000 10100100. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100010 10100100