MONGOLIAN MANCHU COMMA·U+1808

Character Information

Code Point
U+1808
HEX
1808
Unicode Plane
Basic Multilingual Plane
Category
Other Punctuation

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A0 88
11100001 10100000 10001000
UTF16 (big Endian)
18 08
00011000 00001000
UTF16 (little Endian)
08 18
00001000 00011000
UTF32 (big Endian)
00 00 18 08
00000000 00000000 00011000 00001000
UTF32 (little Endian)
08 18 00 00
00001000 00011000 00000000 00000000
HTML Entity
᠈
URI Encoded
%E1%A0%88

Description

The Unicode character U+1808, known as the Mongolian Manchu Comma, plays a significant role in digital texts by serving as a punctuation mark in the Manchu script. This typographical element is essential for maintaining the integrity of written communication in the Manchu language, which has historical and cultural significance as it was used by the Aisin Gioro (Manchu royal family) and the Qing Dynasty in China. In digital text, the Mongolian Manchu Comma is indispensable for maintaining accurate syntax and readability, ensuring that text in the Manchu script flows seamlessly, just as it does in other languages with established punctuation marks. Its presence in the Unicode Standard demonstrates a commitment to preserving linguistic diversity and cultural heritage through digital typography.

How to type the symbol on Windows

Hold Alt and type 6152 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1808. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1808 to binary: 00011000 00001000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100000 10001000