NEW TAI LUE LETTER HIGH MA·U+1996

Character Information

Code Point
U+1996
HEX
1996
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A6 96
11100001 10100110 10010110
UTF16 (big Endian)
19 96
00011001 10010110
UTF16 (little Endian)
96 19
10010110 00011001
UTF32 (big Endian)
00 00 19 96
00000000 00000000 00011001 10010110
UTF32 (little Endian)
96 19 00 00
10010110 00011001 00000000 00000000
HTML Entity
ᦖ
URI Encoded
%E1%A6%96

Description

U+1996 is a typographical character known as the "NEW TAI LUE LETTER HIGH MA." In the realm of digital text, it plays a significant role in representing the New Tai Lue script, which is predominantly used among the Tai Lue ethnic group residing in the northern regions of Thailand and Myanmar. This script, developed from the ancient Brahmi script, possesses a rich linguistic history that dates back centuries. U+1996 specifically represents the phoneme /m˥/, which is an important component for constructing words and phrases within the New Tai Lue language. The character's usage facilitates accurate communication in this language, thus preserving cultural heritage and promoting linguistic diversity in digital text environments.

How to type the symbol on Windows

Hold Alt and type 6550 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1996. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1996 to binary: 00011001 10010110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100110 10010110