NEW TAI LUE LETTER LOW MA·U+1999

Character Information

Code Point
U+1999
HEX
1999
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A6 99
11100001 10100110 10011001
UTF16 (big Endian)
19 99
00011001 10011001
UTF16 (little Endian)
99 19
10011001 00011001
UTF32 (big Endian)
00 00 19 99
00000000 00000000 00011001 10011001
UTF32 (little Endian)
99 19 00 00
10011001 00011001 00000000 00000000
HTML Entity
ᦙ
URI Encoded
%E1%A6%99

Description

U+1999, also known as NEW TAI LUE LETTER LOW MA, is a specialized typographic character used primarily in digital text. It plays a vital role in the representation of the New Tai Lue language, which is predominantly spoken by the Tai Lue people residing in regions such as China's Yunnan Province and Myanmar's Shan State. As part of the Unicode system, U+1999 enables accurate encoding of this unique script in digital platforms, facilitating communication and preserving cultural heritage. The character contributes to a rich linguistic context that showcases the diversity of world languages and supports the ongoing efforts to maintain and revitalize minority languages.

How to type the symbol on Windows

Hold Alt and type 6553 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1999. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1999 to binary: 00011001 10011001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100110 10011001