NEW TAI LUE LETTER LOW THA·U+1992

Character Information

Code Point
U+1992
HEX
1992
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A6 92
11100001 10100110 10010010
UTF16 (big Endian)
19 92
00011001 10010010
UTF16 (little Endian)
92 19
10010010 00011001
UTF32 (big Endian)
00 00 19 92
00000000 00000000 00011001 10010010
UTF32 (little Endian)
92 19 00 00
10010010 00011001 00000000 00000000
HTML Entity
ᦒ
URI Encoded
%E1%A6%92

Description

U+1992 is a character in the Unicode standard that represents the "NEW TAI LUE LETTER LOW THA" (ດ). This symbol is primarily used in digital text within the Tai Leu script, which is an abugida writing system predominantly used in Laos for the Lao language. The New Tai Lue script is a development of the Lao script and is often employed in the northeastern region of Laos, specifically among the Tai Leu ethnic group. U+1992 plays a crucial role in representing the phonetic and phonological structure of the Lao language by signifying a distinct sound or syllable within words. In the digital realm, this character ensures accurate text representation for users who converse in languages that utilize the New Tai Lue script, thereby promoting cultural heritage preservation and linguistic diversity on the internet.

How to type the symbol on Windows

Hold Alt and type 6546 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1992. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1992 to binary: 00011001 10010010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100110 10010010