NEW TAI LUE THAM DIGIT ONE·U+19DA

Character Information

Code Point
U+19DA
HEX
19DA
Unicode Plane
Basic Multilingual Plane
Category
Other Number

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A7 9A
11100001 10100111 10011010
UTF16 (big Endian)
19 DA
00011001 11011010
UTF16 (little Endian)
DA 19
11011010 00011001
UTF32 (big Endian)
00 00 19 DA
00000000 00000000 00011001 11011010
UTF32 (little Endian)
DA 19 00 00
11011010 00011001 00000000 00000000
HTML Entity
᧚
URI Encoded
%E1%A7%9A

Description

U+19DA, or NEW TAI LUE THAM DIGIT ONE, is a character from the Unicode standard, specifically within the New Tai Lue numerals group. These numerals are primarily used in the written form of the New Tai Lue language, which is spoken by the Tai Lue people native to southern China and northern Myanmar. The digit one represents the smallest value in New Tai Lue Tham numerals, akin to how '1' represents this value in the Hindu-Arabic numeral system used predominantly worldwide. As with other digits within the New Tai Lue Tham numerals, U+19DA helps facilitate mathematical calculations and numerical representation in written texts for the New Tai Lue language. Its usage is limited to digital text that necessitates the use of these specific numerals, primarily in academic or cultural contexts focused on the New Tai Lue language and its literature.

How to type the symbol on Windows

Hold Alt and type 6618 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+19DA. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+19DA to binary: 00011001 11011010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100111 10011010