NEW TAI LUE VOWEL SIGN AE·U+19B6

Character Information

Code Point
U+19B6
HEX
19B6
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 A6 B6
11100001 10100110 10110110
UTF16 (big Endian)
19 B6
00011001 10110110
UTF16 (little Endian)
B6 19
10110110 00011001
UTF32 (big Endian)
00 00 19 B6
00000000 00000000 00011001 10110110
UTF32 (little Endian)
B6 19 00 00
10110110 00011001 00000000 00000000
HTML Entity
ᦶ
URI Encoded
%E1%A6%B6

Description

U+19B6, also known as NEW TAI LUE VOWEL SIGN AE, is a typographic character utilized primarily in digital text to represent the "ae" sound found in the New Tai Lue language. This language is predominantly spoken by the Tai Lue ethnic group in Northern Laos and Southern China's Yunnan Province. In the context of this script, U+19B6 serves a significant role as it helps convey proper pronunciation and meaning within the New Tai Lue text, ensuring accurate communication among its speakers. As an essential component of this language's typography, U+19B6 contributes to the preservation and understanding of New Tai Lue culture, linguistics, and history.

How to type the symbol on Windows

Hold Alt and type 6582 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+19B6. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+19B6 to binary: 00011001 10110110. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10100110 10110110