OGHAM LETTER PEITH·U+169A

Character Information

Code Point
U+169A
HEX
169A
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 9A 9A
11100001 10011010 10011010
UTF16 (big Endian)
16 9A
00010110 10011010
UTF16 (little Endian)
9A 16
10011010 00010110
UTF32 (big Endian)
00 00 16 9A
00000000 00000000 00010110 10011010
UTF32 (little Endian)
9A 16 00 00
10011010 00010110 00000000 00000000
HTML Entity
ᚚ
URI Encoded
%E1%9A%9A

Description

U+169A, also known as Ogam Letter Peith, holds a significant position in the field of typography and Unicode. This character is an essential component of the Old Irish script called Ogham, which was utilized from the 2nd century AD to the 8th or 9th century. Its primary usage in digital text serves as an important element for typographers working on historical texts or those engaged in preserving ancient scripts. The character is also valuable for linguists studying the ancient Celtic language of Ireland and scholars interested in the history of writing systems. While U+169A does not have widespread use in modern typography, its inclusion in Unicode ensures that it can be accurately represented and preserved for future generations to study and appreciate this unique aspect of cultural heritage.

How to type the symbol on Windows

Hold Alt and type 5786 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+169A. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+169A to binary: 00010110 10011010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10011010 10011010