ORIYA LETTER DDHA·U+0B22

Character Information

Code Point
U+0B22
HEX
0B22
Unicode Plane
Basic Multilingual Plane
Category
Other Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E0 AC A2
11100000 10101100 10100010
UTF16 (big Endian)
0B 22
00001011 00100010
UTF16 (little Endian)
22 0B
00100010 00001011
UTF32 (big Endian)
00 00 0B 22
00000000 00000000 00001011 00100010
UTF32 (little Endian)
22 0B 00 00
00100010 00001011 00000000 00000000
HTML Entity
ଢ
URI Encoded
%E0%AC%A2

Description

The Unicode character U+0B22 is known as the Oriya Letter DDHA. In digital text, it plays a significant role in representing the Devanagari script, specifically in the Oriya language. This character is integral to the accurate representation of the Oriya language in digital spaces such as websites and software interfaces. The Oriya language, primarily spoken in the Indian state of Odisha, has a rich cultural and linguistic history. U+0B22 contributes to preserving this heritage by allowing for the correct display and encoding of text in Oriya. Its use helps maintain the integrity of written communication in the language and supports the linguistic diversity of the global digital landscape. Overall, the Oriya Letter DDHA is a vital component for accurate digital representation of the Oriya script within Unicode standard.

How to type the symbol on Windows

Hold Alt and type 2850 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+0B22. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+0B22 to binary: 00001011 00100010. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100000 10101100 10100010