LATIN SMALL LETTER ESH WITH PALATAL HOOK·U+1D8B

Character Information

Code Point
U+1D8B
HEX
1D8B
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 8B
11100001 10110110 10001011
UTF16 (big Endian)
1D 8B
00011101 10001011
UTF16 (little Endian)
8B 1D
10001011 00011101
UTF32 (big Endian)
00 00 1D 8B
00000000 00000000 00011101 10001011
UTF32 (little Endian)
8B 1D 00 00
10001011 00011101 00000000 00000000
HTML Entity
ᶋ
URI Encoded
%E1%B6%8B

Description

The Unicode character U+1D8B, known as the Latin Small Letter Esh with Palatal Hook, serves a significant role within the realm of digital text. This character is primarily used in the Ainu language, which is spoken by the indigenous people of Japan and Russia. In this context, it holds linguistic value and contributes to the preservation of Ainu culture. U+1D8B exhibits a unique typographic feature - the palatal hook - that distinguishes it from other Latin letters. Its inclusion in digital text ensures accurate representation and maintains the integrity of Ainu literature, helping to keep this endangered language alive. Overall, U+1D8B is an essential character for digital communication, particularly within the context of minority languages and linguistic preservation.

How to type the symbol on Windows

Hold Alt and type 7563 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D8B. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D8B to binary: 00011101 10001011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10001011