LATIN SMALL LETTER OPEN E WITH RETROFLEX HOOK·U+1D93

Character Information

Code Point
U+1D93
HEX
1D93
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 93
11100001 10110110 10010011
UTF16 (big Endian)
1D 93
00011101 10010011
UTF16 (little Endian)
93 1D
10010011 00011101
UTF32 (big Endian)
00 00 1D 93
00000000 00000000 00011101 10010011
UTF32 (little Endian)
93 1D 00 00
10010011 00011101 00000000 00000000
HTML Entity
ᶓ
URI Encoded
%E1%B6%93

Description

U+1D93, also known as Latin Small Letter Open E with Retroflex Hook, is a unique character in the Unicode standard that represents an alphabetic symbol primarily used in digital text. This letter is part of the Extended Latin alphabet, which consists of additional letters and symbols used for various languages and scripts beyond the basic Latin alphabet. The U+1D93 character holds a significant role in linguistic and cultural contexts where retroflex consonants are prevalent, such as in certain Indian languages like Hindi or Malayalam. In these languages, the Retroflex Hook symbol aids in representing the sound of a retroflex consonant, which is produced when the tip of the tongue curls back to touch the palate behind the upper teeth. This character is crucial for accurate transcription and representation of these linguistic sounds in digital text, thus playing a vital technical role in typography and text encoding systems.

How to type the symbol on Windows

Hold Alt and type 7571 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D93. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D93 to binary: 00011101 10010011. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10010011