LATIN SMALL LETTER P WITH PALATAL HOOK·U+1D88

Character Information

Code Point
U+1D88
HEX
1D88
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 88
11100001 10110110 10001000
UTF16 (big Endian)
1D 88
00011101 10001000
UTF16 (little Endian)
88 1D
10001000 00011101
UTF32 (big Endian)
00 00 1D 88
00000000 00000000 00011101 10001000
UTF32 (little Endian)
88 1D 00 00
10001000 00011101 00000000 00000000
HTML Entity
ᶈ
URI Encoded
%E1%B6%88

Description

The Unicode character U+1D88, known as "LATIN SMALL LETTER P WITH PALATAL HOOK," is an alphabetic character primarily used in digital text to represent a modified version of the lowercase letter 'p.' This unique symbol is part of the Latin Extended-B script block and was added to Unicode version 5.1 in October 2006. U+1D88 holds a notable role in typography, particularly for those involved in linguistics or cultural studies, as it serves to differentiate between similar phonetic sounds in certain languages. The palatal hook modification is an essential diacritic that alters the pronunciation of the letter 'p' from a bilabial plosive to a palato-alveolar plosive, making it a crucial element in accurate transcription and representation of certain dialects or languages. As a result, U+1D88 is an important tool for linguists, anthropologists, and language learners seeking to accurately represent the sounds and nuances of diverse languages and dialects within digital text.

How to type the symbol on Windows

Hold Alt and type 7560 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D88. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D88 to binary: 00011101 10001000. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10001000