LATIN SMALL LETTER X WITH PALATAL HOOK·U+1D8D

Character Information

Code Point
U+1D8D
HEX
1D8D
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 8D
11100001 10110110 10001101
UTF16 (big Endian)
1D 8D
00011101 10001101
UTF16 (little Endian)
8D 1D
10001101 00011101
UTF32 (big Endian)
00 00 1D 8D
00000000 00000000 00011101 10001101
UTF32 (little Endian)
8D 1D 00 00
10001101 00011101 00000000 00000000
HTML Entity
ᶍ
URI Encoded
%E1%B6%8D

Description

The Unicode character U+1D8D, known as Latin Small Letter X with Palatal Hook, is a typographical variation of the lowercase letter "x". This specific glyph is designed to include a small hook in its tail, similar to the palatalization found in some letters of certain languages. In digital text, this character can be used for artistic purposes or as a unique design element in graphic design projects and typography. Although it does not have a specific cultural, linguistic, or technical context, the Latin Small Letter X with Palatal Hook is an interesting example of how the Unicode standard allows for diverse and creative representations of letters beyond their traditional forms. It demonstrates the versatility of written communication and showcases the extensive range of characters available in digital text systems.

How to type the symbol on Windows

Hold Alt and type 7565 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D8D. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D8D to binary: 00011101 10001101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10001101