MODIFIER LETTER SMALL BARRED O·U+1DB1

Character Information

Code Point
U+1DB1
HEX
1DB1
Unicode Plane
Basic Multilingual Plane
Category
Modifier Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B6 B1
11100001 10110110 10110001
UTF16 (big Endian)
1D B1
00011101 10110001
UTF16 (little Endian)
B1 1D
10110001 00011101
UTF32 (big Endian)
00 00 1D B1
00000000 00000000 00011101 10110001
UTF32 (little Endian)
B1 1D 00 00
10110001 00011101 00000000 00000000
HTML Entity
ᶱ
URI Encoded
%E1%B6%B1

Description

The Unicode character U+1DB1 is known as the "MODIFIER LETTER SMALL BARRED O". It plays a critical role in digital text, particularly within the realm of linguistics and typography. This character serves as an indicator for phonological and phonetic transcriptions, specifically when transcribing sounds in languages such as Korean or Vietnamese. By employing this character, typographers can accurately depict specific pronunciation characteristics that are unique to certain languages. The "MODIFIER LETTER SMALL BARRED O" is particularly useful for linguists conducting research and studies on these languages, as it provides a precise tool for denoting sounds within their transcriptions. Although this character may not be commonly used in everyday digital communication, its significance lies in its ability to accurately represent specific linguistic nuances.

How to type the symbol on Windows

Hold Alt and type 7601 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1DB1. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1DB1 to binary: 00011101 10110001. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110110 10110001