LATIN LETTER AIN·U+1D25

Character Information

Code Point
U+1D25
HEX
1D25
Unicode Plane
Basic Multilingual Plane
Category
Lowercase Letter

Character Representations

Click elements to copy
EncodingHexBinary
UTF8
E1 B4 A5
11100001 10110100 10100101
UTF16 (big Endian)
1D 25
00011101 00100101
UTF16 (little Endian)
25 1D
00100101 00011101
UTF32 (big Endian)
00 00 1D 25
00000000 00000000 00011101 00100101
UTF32 (little Endian)
25 1D 00 00
00100101 00011101 00000000 00000000
HTML Entity
ᴥ
URI Encoded
%E1%B4%A5

Description

The Unicode character U+1D25, known as the Latin Letter Ain, is a letter used in the Nüshu script, which was historically employed by women in China's Hunan province for written communication. Nüshu, a logosyllabic writing system, allows its users to express both phonetic and semantic elements of language. The Latin Letter Ain is one of 26 basic Nüshu characters, each representing either an initial or a final consonant, with tones indicated by diacritics or vowel marks placed above or below the base character. Although Nüshu is not widely used today, efforts are being made to preserve and promote this unique script as part of China's cultural heritage.

How to type the symbol on Windows

Hold Alt and type 7461 on the numpad. Or use Character Map.

  1. Step 1: Determine the UTF-8 encoding bit layout

    The character has the Unicode code point U+1D25. In UTF-8, it is encoded using 3 bytes because its codepoint is in the range of 0x0800 to 0xffff.

    Therefore we know that the UTF-8 encoding will be done over 16 bits within the final 24 bits and that it will have the format: 1110xxxx 10xxxxxx 10xxxxxx
    Where the x are the payload bits.

    UTF-8 Encoding bit layout by codepoint range
    Codepoint RangeBytesBit patternPayload length
    U+0000 - U+007F10xxxxxxx7 bits
    U+0080 - U+07FF2110xxxxx 10xxxxxx11 bits
    U+0800 - U+FFFF31110xxxx 10xxxxxx 10xxxxxx16 bits
    U+10000 - U+10FFFF411110xxx 10xxxxxx 10xxxxxx 10xxxxxx21 bits
  2. Step 2: Obtain the payload bits:

    Convert the hexadecimal code point U+1D25 to binary: 00011101 00100101. Those are the payload bits.

  3. Step 3: Fill in the bits to match the bit pattern:

    Obtain the final bytes by arranging the paylod bits to match the bit layout:
    11100001 10110100 10100101